Question

Construct a A PQR in which QR = 5.5 cm, P = 45° and Q=30°​

Answer 1

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Steps of Construction:

Steps of Construction:(i) Draw a line segment QR = 5.5 cm

(ii) At Q, draw a ray making an angle of 90° and cut off QP = 5.5 cm.

(ii) At Q, draw a ray making an angle of 90° and cut off QP = 5.5 cm.(iii) Join PR.

(ii) At Q, draw a ray making an angle of 90° and cut off QP = 5.5 cm.(iii) Join PR.∆PQR is an isosceles triangle.

(ii) At Q, draw a ray making an angle of 90° and cut off QP = 5.5 cm.(iii) Join PR.∆PQR is an isosceles triangle.(iv) Draw the angle bisector of ∠PQR. It is the line of symmetry. Since the triangle is an isosceles.

(ii) At Q, draw a ray making an angle of 90° and cut off QP = 5.5 cm.(iii) Join PR.∆PQR is an isosceles triangle.(iv) Draw the angle bisector of ∠PQR. It is the line of symmetry. Since the triangle is an isosceles.∴ It has only one line of symmetry.