Question

Construct a AABC such that AB = 6 cm,
ZBAC = 45° and ZABC = 60°.​

Answer 1

Answer:

u need to use practical geometry

Step-by-step explanation:

step 1: draw a 6cm line segment and name it AB

step 2: on point A construct a 90 degree angle.

step 3: bisect it to 45 degrees and draw a line about 9 to 10 cm

step 4: now construct an angle of 60 degree on point B and draw a line. extend the line until it intersects the line of 45 degree.

step 5: now name the point where the 2 line intersect C.

Construct 45 degree angle-

1) Use ruler and draw a Line segment OB of any convenient length.

2). Now use compass and open it to any convenient radius. And with O as center , draw an arc which cuts line segment OB at X .

3). Again use compass and opened to the same radius (as of step 2). And with X as center , draw an arc which cuts first arc at D .

4). Again use compass and opened to the same radius (as of step 2). And with D as center , draw another arc which cuts first arc at C .

5). Again use compass and opened to the same radius (as of step 2). And With C & D as center , draw two arcs which cuts each other at E .

6). Join OE and extent it to A . (as shown below)

7). Above formed angle AOB = 90 Degree

8). Again use compass and open it to any convenient radius. And with O as center , draw an arc which cuts line segment OB at P and OA at Q .

Construct 60 degree angle-

1) Use Ruler - Draw a Line segment QR of any convenient length.

2). Now use compass and open it to any convenient radius. And with Q as center draw an arc which cuts line segment QR at y .

3). Again use compass and opened to the same radius (as of step 2). And With y as center , draw an arc which cuts previous arc at X .

4). Join QX and extent it to P .

5). Above formed angle PQR = 60 Degree