construct a ∆ABC A=45°,B=90° and AB++BC+CA=14 CM.
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Hlo friend.. Cutiepie Here.
Here is ur answer :
Step 1 : Draw a line segment XY 14 cm.
Step 2 : Draw an angle of 45 on point X.
Step 3 : Draw an angle of 90 on point Y.
Step 4 : Draw bisectors of both the angles and mark their intersection point as A.
Step 5 : Draw a perpendicular bisector of AX and AY meeting XY in B and C respectively.
Step 6 : Join AB and AC to obtain the required triangle ABC.
HOPE IT HELPS YOU...
REGARDS
@sunita
Here is ur answer :
Step 1 : Draw a line segment XY 14 cm.
Step 2 : Draw an angle of 45 on point X.
Step 3 : Draw an angle of 90 on point Y.
Step 4 : Draw bisectors of both the angles and mark their intersection point as A.
Step 5 : Draw a perpendicular bisector of AX and AY meeting XY in B and C respectively.
Step 6 : Join AB and AC to obtain the required triangle ABC.
HOPE IT HELPS YOU...
REGARDS
@sunita
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