Question

Construct a ΔABC AB=5cm ∠A = 900 and AC= 6cm.

Answer 1

Answer:

☞draw line segment AB length of 5cm

☞Taking 7cms as radius,A as centre, draw an arc

☞Taking 6cm as radius and b as centre,draw another arc

☞let c be the point where the two arcs intersect Join AC&BC and label the sides

☞thus, ABC is the required triangle

Answer 2

Answer:

Steps of construction :

1) Draw a line segment AB = 5 cm.

2) Make ∠ABC=75 o .

3) Cut off BC = 7 cm.

4) Join AC.

Therefore, △ABC is the required triangle.