Question

Construct a ∆ABC angle B =70°,AB =4.8 cm,and BC =5.2 cm
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Answer 1

$\triangle ABC$ is the required triangle.

Step-by-step explanation:

Given,

Construct  $\triangle ABC$ where $\angle B =70\ degree,AB =4.8\ cm\ and\ BC=5.2\ cm$

Following steps:

• Draw a line segments $BC=5.2\ cm$ using scale.
• By using protector draw an angle $70\ degree$ at $B$ like $\angle CBX=70\ degree$
• Take $B$ as center and $4.8\ cm$ as radius draw an arc $A$ on line $BX$ like $AB=4.8\ cm$
• Join $AC$

Hence, $\triangle ABC$ is the required triangle.

Answer 2

∆ABC is constructed with ∠B = 70° , AB = 4.8 cm and BC = 5.2 cm

Given:

∆ABC

∠B = 70°

AB = 4.8 cm

BC = 5.2 cm

To Find:

Construct  ∆ABC

Solution:

Step 1: Draw a line segment AB=4.8 cm

Step 2 : Draw a ray BX at an angle of 70° on AB using Protractor.

Step 3 : Using compass width = 5.2 cm and Taking B as center cut angle drawn at C

Step 4 : Join AC

∆ABC is constructed

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