Math, asked by anshuprasad88005, 3 months ago

construct a ABC in which BC =5.3CM, LB =45° LA=75 °​

Answers

Answered by Braɪnlyємρєяσя
2

Step-by-step explanation:

Draw a line segment AB of length 5.8cm.

2. Draw a line segment BX, sufficiently large such that ∠ABX=60

.

3. From the segment BX, cut off line segment BD of length 8.4cm.

4. Join AD.

5. Draw the perpendicular bisector of AD and let it meet BD at C.

6. Join AC.

Then ABC is the required triangle.

Attachments:
Answered by HorridAshu
0

Step-by-step explanation:

☛Draw a line segment AB of length 5.8cm.

☛ Draw a line segment BX, sufficiently large such that ∠ABX=60

☛ From the segment BX, cut off line segment BD of length 8.4cm.

☛ Join AD.

☛ Draw the perpendicular bisector of AD and let it meet BD at C.

☛ Join AC.

∴Then ABC is the required triangleΔ.

Attachments:
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