Construct a ∆ABC whose perimeter is 8.2cm (AB +BC+CA cm) and the base angles are 45°and 60°also write step of constructions.
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Answer:pta ni
Step-by-step explanation:
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Step-by-step explanation:
1. Draw a line segment PQ = AB + BC + CA = 12 cm.
2. Make ∠ LPQ= 45° and ∠ MQP = 60°
3. Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.
4. Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.
5. Join AB and AC
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