Question

construct a angel ABC in which AB=6cm ,BC=4cm,CA=5cm​

Answer 1

Answer:

$\tan( \alpha ) = \frac{oppsite}{adjacent}$

$\tan( \alpha ) = \frac{5}{4}$

$\cos( \beta ) = \frac{adjacent}{hypotenuce}$

$\cos( \beta ) = \frac{4}{6}$

$\cos( \beta ) = \frac{2}{3}$

The angle may be 90°

Answer 2

just watch it on youtube i bet you can learn it