Question

find the distance and displacement of a particle which is
move a circular path when
in complete
3/4 part of the
circle. Radius of circle is 28.
​

Answer 1

Answer:

perimeter of circle is =2¶r

perimeter of circle is = 2× 3.14×28 =175.84

primeter of a circle is 175.84

$1 - \frac{3}{4} = \frac{1}{4}$

$displacement \: = \sqrt{ {r}^{2} } + {r}^{2}$

complete root √r2 +r2

$displacement = \sqrt{2 {r}^{2} }$

$displacement = 2r$

$displacement = 2 \times 28 = 56$

distance =3/4 ×2¶r

distance = 3¶r/2 = 131.88