Question

Construct a Axyz in which Zy = 30°, Zz = 90° and perimeter of Axyz is
11 cm​

Answer 1

Step-by-step explanation:

1....Draw a line AB equal to perimeter..i.e 11 2...draw bisector of 30° from A as centre.(15°)

3..draw bisector of 90° from B as centre.(45°)

4...let these lines intersect at X

5...draw perpendicular bisector of AZ and BZ let them intersect AB at Y And Z

6..join xyz u will get required triangle...

this is ncert question..u cn get it on google.