Construct a cyclic quadrilateral ABCD where AB 3 cm, BC 6 cm, CA 4 cm and AD 2 cm. Also, construct a quadrilateral similar to ABCD whose sides are 1.5 times the corresponding sides of ABCD
Answers
As, it is given that, AB=3 cm, BC=6 cm, CA=4 cm and AD=2 cm
Now, Draw AB=3 cm,
From B mark an arc BC=6 cm.
And from A , mark arc such that AC=4 cm
Now draw perpendicular bisector of chord AB, BC and AC.The point where these perpendicular bisectors meet is center of the circle.
Mark this center as O.
Taking O as center ,and Either of OA , OB, or OC as radius draw circles passing through vertices A,B and C .
From A mark arc on circle , such that AD=2 cm.Join C and D.
This is required cyclic Quadrilateral ABCD.
To Draw a quadrilateral similar to ABCD whose sides are 1.5 times the corresponding sides of ABCD can be drawn by Quadrilateral having sides , PQ=3 ×1.5=4.5 cm, QR=6 ×1.5=9 cm, PR=4 ×1.5= 6 cm,PS=2 ×1.5=3 cm.
Follow the method described above to draw cyclic Quadrilateral ABCD.
Draw PQ.
From P mark............
Draw perpendicular bisector of sides,.....
This is required cyclic Quadrilateral PQRS.
