Question

construct a equilateral triangle of altitude 4.5cm

Answer 1

Take any point L on this line

.Construct perpendicular AL on PQ.Cut a line segment AD from D equal to 4.5 cm

.Make angles equal to 30° at

A on both sides of AD, say ∠CAD

and ∠BAD where B and C lie on XY.Then,

ABC is the required triangle.Justification

:Since ∠A = 30° + 30° = 60° and AL ⊥ BC,

Answer 2

this is your triangle