Question

Solve this question and answer please quick.

Answer 1

I think this one is....

Answer 2

Given 39y^3(50y^2 - 98)/ 26y^2(5y + 7) can be written as..
 
        = 13 * 3y^3(50y^2 - 98)/13 * 2y^2(5y + 7)

        = 3y^3(50y^2 - 98)/2y^2(5y + 7)

        = 3y(50y^2 - 98)/2(5y + 7)

       = 2 * 3y(25y^2 - 49)/2(5y + 7)

       = 6y(25y^2 - 49)/2(5y + 7)

       = 3y(25y^2 - 49)/(5y + 7)

We know that (a^2 - b^2) = (a - b)(a+b)

       = 3y(5y - 7)(5y + 7)/(5y + 7)

      =  3y(5y - 7)  (or) 15y^2 - 21y.


Hope this helps!