Question

Construct a kite whose diagonals are 8 cm and 12 cm and one of its side is 5 cm. ​

Answer 1

Answer:

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Step-by-step explanation:

Draw a line segment AC=16cm

⇒ Draw a perpendicular bisector of AC, which intersect AC at point O.

⇒ Take O as center with radius 6cm and draw an arc above and below on perpendicular, We get point B and D

⇒ Join AB,BC,CD and AD

∴ ABCD is required rhombus.

The properties which we have used are :

⇒ The intersection of the diagonals of a rhombus form 90 degree angles. This means that they are perpendicular.

⇒ The diagonals of a rhombus bisect each other. This means that they cut each other in half.