Math, asked by vibhu27, 1 year ago

construct a <XYZ in which <X=45°, <Y=60°and XY=4.7cm.

Answers

Answered by kinkyMkye
1
1) Draw a XY of length 4.7cm
2) Draw a large arc with x as center and radius <4.7cm which meets the line xy at x'
3) with x' as center cut the arc with same radius at x"
4) with x'' as center cut the arc with same radius at x"'
5) with x' and x" as centers cut the arc with large radius, lets call it P
6) join P and X and let it cut the large arc at P'
7) with P', X' as center, draw arcs to intersect at P" =>∠X =45°

8)Draw a large arc with Y as center and radius <4.7cm which meets the line xy at Y'
9) with Y' as center cut the arc with same radius at Y" =>∠60°
10) connect and extend yy" and xtend to cut Xp" at Z

 hence the triangle XYZ
Answered by milan123mathew
0

Step-by-step explanation:

1) Draw a XY of length 4.7cm 2) Draw a large arc with x as center and radius <4.7cm which meets the line xy at x' 3) with x' as center cut the arc with same radius at x" 4) with x" as center cut the arc with same radius at x" 5) with x' and x" as centers cut the arc with large radius, lets call it P 6) join P and X and let it cut the large arc at P' 7) with P', X' as center, draw arcs to intersect at P" =>LX =45° 8)Draw a large arc with Y as center and radius <4.7cm which meets the line xy at Y' 9) with Y' as center cut the arc with same radius at Y" =>0° 10) connect and extend yy" and xtend to cut Xp" at Z hence the triangle XYZ

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