Question

construct a paralellogram abcd in which angle A : angle B =1:2 and AB = 6cm and BC = 5cm​

Answer 1

Answer:

Step 1 : Draw a rough diagram and mark the given measurements.

Step 2 : Draw a line segment AB = 6 cm.

Step 3 : At B on

AB

make ∠ ABX whose measure is 80

o

.

Step 4 : With B as centre draw an arc of radius 5.5 cm and let it cuts

BX

at C.

Step 5 : With C and A as centres draw arcs of radii 6 cm and 5.5 cm repectively and let them cut at D.

Step 6 : Join

AD

and

CD

. ABCD is the required parallelogram.

Step 7 : From C draw

CE

⊥

AB

and measure the length of CE. CE = h = 5.4 cm. AB = b = 6 cm.

Calculation of area:

In the parallelogram ABCD, b = 6 cm and h = 5.4 cm.

Area of the parallelogram ABCD = b h = 6 *5.4 = 32.4 cm

2

solution

Answer 2

Answer:

Answer is in the image attached