Question

construct a parallelogram ABCD,AB=6.8cm,AC=8cm,BD=7.3cm

Answer 1

Thus, $ABCD$ is the required parallelogram.

Step-by-step explanation:

Given,

Construct a parallelogram $ABCD$ where $AB=6.8cm$,$AC=8cm$ and $BD=7.3cm$

We know that diagonals of a parallelogram bisect each other.

Diagonal are cuts at point $O$

∴$AO=\frac{1}{2}\times AC= \frac{1}{2}\times 8=4cm$

And $BO=\frac{1}{2}\times BD= \frac{1}{2}\times 7.3=3.65cm$

Following steps:

• Draw a line $AB=6.8cm$
• Take measure of $4cm$ draw a curve from point $A$
• Also from point $B$,take measure $3.65cm$ and draw a curve which cuts before curve at point $O$
• Join $AO$ and $BO$
• Extend $AO$ to a point $C$ such as $OC=4cm$ or $AC=8cm$
• Extend $BO$ to a point $D$ such that $OD=3.65cm$ or $BD=7.3cm$
• Join $BC$,$CD$ and $AD$

Now, $ABCD$ is the required parallelogram.

Answer 2

Answer:

no need of any other answer

up answer if 100% correct

good job for this correct ans