Question

Construct a parallelogram ABCD, given that
AB = 3.8 cm, BC = 5.7 cm and /_B = 75°.​

Answer 1

Answer:

first draw that much which is given in question

Step-by-step explanation:

then line ab =3.8 line bc=5.7 then angle b = angle d . and angle A + angle B =180degree so angle a is 105 degree angle b = angle c same process angle c =105 draw both line a and c you form the trapezium and you will get angle d . angle d =75 degree. plz marke as brainlist

Answer 2

Step-by-step explanation:

1. draw AB of 3.8 cm

2. make angle of 90° on angle B .

3 now make angle of 75° by keeping compass on point 60° and 90° it will intersect at 75°

4. join point b and continue drawing line after the point of interaction

5. measure 5.7 with compass and make a small cut on line BC

6. join AC

CONFRATS YOUR TRIANGLE IS COMPLETE NOW