Find area of equilateral triangle ABC, where A : (1, –3) and BC
2x-y+3=0
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Answer:
perpendicular distance of A from BC =
{(2×1) + (-1)×(-3) + 3}/√((2^2)+(1^2))
= ((2+3+3)/(√(4+1))
=8/√5 = (√3/2)×a where is the side of equilateral triangle. This gives
a = 16/√15
Area of equilateral triangle = (√3/4)×a^2
put this value of a in this formula
A = (√3/4)×16×16/15
=64√3/15 Ans
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