Construct a parallelogram ABCD in which AB =4.2cm,BC=3.8cm and angle D=115. No spam 100% report no another question
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Answer:
Question 1:
Construct a quadrilateral ABCD in which AB = 4.2 cm, BC = 6 cm, CD = 5.2 cm, DA = 5 cm and AC = 8 cm.
ANSWER:
Steps of construction:
Step 1: Draw AB=4.2 cm.
Step 2: With A as the centre and radius equal to 8 cm, draw an arc.
Step 3: With B as the centre and radius equal to 6 cm, draw another arc, cutting the previous arc at C.
Step 4: Join BC.
Step 5: With A as the centre and radius equal to 5 cm, draw an arc.
Step 6: With C as the centre and radius equal to 5.2 cm, draw another arc, cutting the previous arc at D.
Step 7: Join AD and CD.
Thus, ABCD is the required quadrilateral.
Step-by-step explanation:
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Hope you understood.
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Answer:
Question 1:
Construct a quadrilateral ABCD in which AB = 4.2 cm, BC = 6 cm, CD = 5.2 cm, DA = 5 cm and AC = 8 cm.
ANSWER:
Steps of construction:
Step 1: Draw AB=4.2 cm.
Step 2: With A as the centre and radius equal to 8 cm, draw an arc.
Step 3: With B as the centre and radius equal to 6 cm, draw another arc, cutting the previous arc at C.
Step 4: Join BC.
Step 5: With A as the centre and radius equal to 5 cm, draw an arc.
Step 6: With C as the centre and radius equal to 5.2 cm, draw another arc, cutting the previous arc at D.
Step 7: Join AD and CD.
Thus, ABCD is the required quadrilateral.
Step-by-step explanation:
sorry for giving another question.
Hope you understood.
I not able to give your questions answers.
GOOD MORNING
DID YOU UNDERSTAND
PLEASE LET ME KNOW.