Math, asked by rsnbhhjk, 12 days ago

Construct a parallelogram ABCD in which AB =4.2cm,BC=3.8cm and angle D=115. No spam 100% report no another question​

Answers

Answered by himanshuak354
15

Answer:

Question 1:

Construct a quadrilateral ABCD in which AB = 4.2 cm, BC = 6 cm, CD = 5.2 cm, DA = 5 cm and AC = 8 cm.

ANSWER:

Steps of construction:

Step 1: Draw AB=4.2 cm.

Step 2: With A as the centre and radius equal to 8 cm, draw an arc.

Step 3: With B as the centre and radius equal to 6 cm, draw another arc, cutting the previous arc at C.

Step 4: Join BC.

Step 5: With A as the centre and radius equal to 5 cm, draw an arc.

Step 6: With C as the centre and radius equal to 5.2 cm, draw another arc, cutting the previous arc at D.

Step 7: Join AD and CD.

Thus, ABCD is the required quadrilateral.

Step-by-step explanation:

sorry for giving another question.

Hope you understood.

I not able to give your questions answers.

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Answered by MrM00N
13

Answer:

Question 1:

Construct a quadrilateral ABCD in which AB = 4.2 cm, BC = 6 cm, CD = 5.2 cm, DA = 5 cm and AC = 8 cm.

ANSWER:

Steps of construction:

Step 1: Draw AB=4.2 cm.

Step 2: With A as the centre and radius equal to 8 cm, draw an arc.

Step 3: With B as the centre and radius equal to 6 cm, draw another arc, cutting the previous arc at C.

Step 4: Join BC.

Step 5: With A as the centre and radius equal to 5 cm, draw an arc.

Step 6: With C as the centre and radius equal to 5.2 cm, draw another arc, cutting the previous arc at D.

Step 7: Join AD and CD.

Thus, ABCD is the required quadrilateral.

Step-by-step explanation:

sorry for giving another question.

Hope you understood.

I not able to give your questions answers.

GOOD MORNING

DID YOU UNDERSTAND

PLEASE LET ME KNOW.

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