Question

Construct a parallelogram ABCD in which AB = 4.5 cm , angle B = 120° and the distance between AB and DC = 3.0 cm

Answer 1

Draw AB 4.5cm and construct 120 degree. Draw BC and AD 3cm, and CD 4.5cm from compass.
Your parallelogram is drawn.
Try to make it in your copy.
Hope it helps you.

Answer 2

Construction of parallelogram ABCD

Step-by-step explanation:

1. First draw a line AB = 4.5 cm.

2. From point A, draw a line AM at angle 90°.

3. From point B, draw a line BN at angle 90°.

4. From point A and point B take an arc of length 3.0 cm. Join point of intersection of arc with line AM and BN, which give line XY.

5. Where XY line is parallel to line AB.

6. From point B draw a line at an angle of 120° with the line AB and intersect with line XY at point. Which give point C.

7. Since ABCD is a parallelogram. Sum of two adjacent angle is 180°.

8. So $\mathbf{\angle A=180-\angle B=180-120=60^{\circ}}$

9.  From point A draw a line at an angle of 60° with the line AB and intersect with line XY at point. Which give point D.

10 Now ABCD is required parallelogram.