Question

construct a parallelogram ABCD in which AB= 4 cm, BC = 3cm and angle A =60°​

Answer 1

Answer:

1

Secondary School Math 5 points

Construt a parallelogram ABCD in which AB=4cm,BC=3cm and angle A=60 degree

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Nitin123451

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Steps of construction.

Made line AB of 4 cm.

After making line made 60°angle at point A.

Now from point B made 180° - 60° = 120° angle because angle B is co - interior angle of angle A.

Now, BC is given 3 cm so from point B and BC as radius mark point C on line made on angle B.

Same as above mark D on line made on angle A with same radius because opposite sides of parallelogram are equal.

Join D to C.

ABCD is required parallelogram.

Answer 2

Answer:

Make line AB of 4 cm.

After making line made 60°angle at point A.

Now from point B made 180° - 60° = 120° angle because angle B is co - interior angle of angle A.

Now, BC is given 3 cm so from point B and BC as radius mark point C on line made on angle B.

Same as above mark D on line made on angle A with same radius because opposite sides of parallelogram are equal.

Join D to C.

ABCD is required parallelogram.