construct a parallelogram ABCD in which AB=5.2cm,BC=4.7cm and AC=7.6cm. steps of construction also
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Ur answer is here ⤵
∠A = 70°
Steps of construction:
1. Draw AD equal to 4.8 cm.
2. Make an angle of 70° at A and cut an arc of 6.5 cm. Name it B.
3. Cut an arc of 4.8 cm from B and 6.5 cm from D. Name it C.
4. Join AB, BC and CD.
5. Measuring the diagonal AC and BD, we get AC equal to 9.2 cm and BD equal to 6.6. cm.
Ur answer is here ⤵
∠A = 70°
Steps of construction:
1. Draw AD equal to 4.8 cm.
2. Make an angle of 70° at A and cut an arc of 6.5 cm. Name it B.
3. Cut an arc of 4.8 cm from B and 6.5 cm from D. Name it C.
4. Join AB, BC and CD.
5. Measuring the diagonal AC and BD, we get AC equal to 9.2 cm and BD equal to 6.6. cm.
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