construct a parallelogram abcd in which ab=6cm bc=5cm and ac=7cm
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20 cm
Step-by-step explanation:
⇒ Draw a line segment AB = 6cm.
⇒ Construct an angle of 60∘ at point B.
⇒ Cut off BC = 4cm.
⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120∘ at point A and C which meet at point D.
⇒ Thus, ABCD is a required parallelogram.
⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )
⇒ Perimeter of parallelogram ABCD=2(a+b)
⇒ 2(6+4) [From( 1 )]
∴ Perimeter of parallelogram ABCD=20cm.
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hopefully it will work ☺️☺️☺️
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