Construct a parallelogram ABCD in which BC= 6cm , CD =4cm and angle C =60 degree
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Answer:
Need to use methods of construction
Step-by-step explanation:
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The construction of a parallelogram ABCD in which BC= 6cm , CD =4cm and angle C =60 degree is as shown below.
Steps of construction:
Draw a line segment BC with a scale of 6 cm
From point C with an angle of 60° draw a line segment.
From point C with a scale of 4 cm draw an arc.
A point where the point and an arc from point C intersect, mark is as D.
From point D, draw a line segment parallel to the line BC.
From point B, with a scale equal to that of the line segment CD = 4 cm, draw an arc.
A point where the line from point D and an arc from point B intersect mark it as A.
Join AB.
Hence the required construction.
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