Question

construct a parallelogram ABCD in which diagonal AC = 3.8 CM diagonal BD = 4.6 cm and the angle between AC and BD is 60°

Answer 1

Answer:

Step-by-step explanation:

in a parallelogram  Diagonals bisects each other

if O is the intersection point of diagonals

Then OA = OC = 3.8/2 = 1.9 cm

OB = OD = 4.6/2 = 2.3 cm

Lets draw first AC = 3.8 cm

Then Take mid point O on AC  such that OS = OC = 1.9 cm

Draw 60° angle at point A on AC(OA)

Take length = 2.3 cm as OD

now join D with A  & C

Extend DO line till B with DB = 4.6 cm

then join B with A & C

Parallelogram is ready

Answer 2

Answer:

The given Parallelogram ABCD can be drawn by following the steps.

Step 1: Draw a line AC=3.8cm

Step 2: Bisect AC at O.

Step 3: At O draw ∠COX=60°

Step 4: Set the value OB=2.3cm and OD=2.3cm (divided the value 4.6 into 2.3 and 2.3

Step 5: Now join AB,BC,CD,DA

We get the required parallelogram ABCD

hope it will help you