Math, asked by arunbhai1234, 6 months ago

construct a parallelogram pqrs ,given that pq=5cm angle p=75° and yz=5cm​

Answers

Answered by chhayuselot
1

Answer:

HD FYI psychiatristfrustration

Answered by Anonymous
6

ANSWER

\large\underline\bold{PLEASE\:REFER\:THE\:ATTACHMENT}

\red{\text{NOTE:-  the parallelogram has 4 sides para,there is no such side yz.}}

\red{\text{ therefore,question is wrong}}

CORRECT QUESTION:-

✯construct a parallelogram pqrs ,given that PQ=5cm angle p=75° and RS=5cm

\large\underline\bold{STEPS\:OF\: CONSTRUCTION,}

\purple{\text{1) draw a line of 5 cm (pq).}}

\sf\purple{2) \:construct\: \angle 60 \degree, \:from \:there\: construct\: \angle 90 \degree}

\sf\purple{3) \:bisect\: the\: angle \:lying \:between \:\angle 60 \degree\: and \:\angle 90 \degree}

\sf\purple {4)\:the \:angle\: obtained\: will\: be\: 75 \degree}

\sf\purple{5) \:now,\: make \:a \:mark\: by \:a \:campass\: of\: 5 cm \:on\: line\: ps}

\sf\purple{6) \:draw \:5 \:cm \:line \:(sr)\:parallel \:to\: pq}

\sf\purple{7) \:join\: rq}

\large\underline\bold{HENCE\:THE\:REQUIRED\:PARELLOGRAM\:IS\:CONSTRUCTED.}

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