Math, asked by Akshita245, 3 months ago

construct a parallelogram PQRS in which PQ=6cm,∆Q=120° and ∆RPQ=30°​

Answers

Answered by mamadhu328
3

Answer:

Iam sorry iam not construction iwant to say steps

follow the steps to construct a parallelogram

1.Take a scale and draw a line 6cm

2.Take a protractor keep a dot on 120 degre.

3.now join Q to r and take another angle on p to s and join each

finally PQRS parallelogram

Attachments:
Answered by krishanmohan11
0

Step-by-step explanation:

Steps of construction:

Steps of construction:Step 1: Draw a line segment of length 6 cm.

Steps of construction:Step 1: Draw a line segment of length 6 cm.Step 2: At the point Q, construct an angle 120° and at point P construct an angle of 30° and extend the lines.

Steps of construction:Step 1: Draw a line segment of length 6 cm.Step 2: At the point Q, construct an angle 120° and at point P construct an angle of 30° and extend the lines.Step 3: Let the intersection of the extended lines be R.

Steps of construction:Step 1: Draw a line segment of length 6 cm.Step 2: At the point Q, construct an angle 120° and at point P construct an angle of 30° and extend the lines.Step 3: Let the intersection of the extended lines be R.Step 4: With center P and radius QR and with centre R and radius PQ, draw arcs intersecting each other at S.

Steps of construction:Step 1: Draw a line segment of length 6 cm.Step 2: At the point Q, construct an angle 120° and at point P construct an angle of 30° and extend the lines.Step 3: Let the intersection of the extended lines be R.Step 4: With center P and radius QR and with centre R and radius PQ, draw arcs intersecting each other at S.Step 5: Join S to P and R.

The following figure shows the required quadrilateral.

Please mark me as Brainliest.

Attachments:
Similar questions