Question

What is the number of neutrons present in one molecule NaAl(OH)4? with explanation. ​

Answer 1

Answer:

58

Explanation:

A Sodium has 12 neutrons

An Aluminum has 14 neutrons

And for a Oxygen,it has 8 neutrons .At last there are 4 Hydrogens but A Hydrogen doesn't have any neutron.

So OH(4) = (8+0)×4 neutrons= 32 neutrons.

So NaAl(OH)4 = 12+14+32 neutrons= 58 neutrons.

Answer 2

Answer:58

Explanation:NaAl(0H)4

23Na; 23-11=12

11

27Al; =27-13=14

13

160; =16-8=8

8

1H; =0

.

. . 12+14+(8+0).4=58 Ans.