Construct a ∆PQR such that RP = 4.5 cm, RQ = 5.5 cm and ∠R = 135°.
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Steps of construction:
(1) Draw a sufficiently long line segment using a ruler.
(2) Locate points A and B on it such that AB = 5 cm.
(3) With A as the centre and radius 3.7 cm, draw an arc.
(4) With B as the centre and radius 4.6 cm, draw another arc that cuts the previous arc at C.
(5) Join AC and BC.
Then, ABC is the required triangle.
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