Question

Construct a ∆PQR with sides PQ=4cm, QR=5cm and RP=7cm​

Answer 1

Answer: Draw  RP as base of measure 7 cm

               take a compass and take measure 5 cm and draw an arc from point R

              and same take measure 4 cm and draw arc from R.

Now join the point got due to intersection of arc.

Triangle is constructed.

Step-by-step explanation:

Answer 2

first we have to draw the line segment PQ which is 4 cm and another line segment QR 5 cm and RP 7cm separately then we have to draw a line of any length after that by using a compass we have to take the measurement of 7 cm and by placing the needle of the compass we will draw 7 cm on the line of any length after that we have to take the needle of the compass at the end point of the 7 cm and from there we have to take the measurement of 5 centimetre which will be above for fit and then we have to take the length 4 cm and by placing the middle of the compass at the starting of the the line of any length we have to draw an Arc and by cutting both the Ark of 4cm and 5cm and by joining the point of the arc with two lines we will get a triangle a scalene triangle