Question

Construct a quadrilateral ABCD in which AB = 3.5 cm , BC= 3.8 cm, CD=DA=4.5 cm and diagonal BD= 5.6 CM.​

Answer 1

Answer:

Step1: Draw a line BD= 5.6cm

Step2: with B as the centre draw an arc of 3.5cm

Step3: with 4.5cm as radius cut the arc drawn in step2 and that point of intersection is A. join BA and DA

Step4: Draw another arc from B with 3.8cm radius on opposite side of BD.

Step5: From D take 4.5cm as radius and cut the arc drawn in step4 and the point of intersection is C. now join BC and CD.

∴ The constructed quadrilateral looks like:

Answer 2

Answer:

The given Quadrilateral ABCD can be drawn by following the steps.

Step 1: Draw a line BD=5.6cm

Step 2: with B as the centre draw an arc of 3.5cm

Step 3: with 4.5cm as radius cut the arc drawn in step 2 and that point of intersection is A. join BA and DA

Step 4: Draw another arc from B with 3.8cm radius on opposite side of BD.

Step 5: From D take 4.5cm as radius and cut the arc drawn in step 4 and the point of intersection is C. now join BC and CD.

∴ The constructed quadrilateral looks like

Step-by-step explanation:

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