Question

construct a quadrilateral ABCD in which AB=4.2cm BC=4.5cm CD=4cm DA=4.8cm and angle A=72°​

Answer 1

Answer:

1) Draw a straight line of length AB = 4.2 cm

2) With the help of a protractor draw a ray with centre as A and angle 72°

3) With A as centre cut the ray of length 4.8 cm

4) with D as centre draw an arc of length 4 cm and with B as centre draw an arc of length 4.5 cm , the two arcs meet at a point and name it as C

5) Join all the line segments

6) Now the required quadrilateral is ABCD

Answer 2

Given : ABCD in which AB=4.2cm, BC=4.5cm, CD=4 cm, DA=4.8 cm and angle A =72°

To Find :  construct Triangle

Solution:

Step 1  :  Draw a line segment AB = 4.2 cm

Step 2 :  Draw a ray at an angle of 72° at A on BA using protractor.

Step 3 :  Using compass width = 4.8 cm and taking A  as center cut the ray  drawn in previous step at D

Step 4 :  Using Compass width = 4.5 cm and taking B as center draw an arc

Step 5 : Using Compass width = 4 cm and taking D as center draw an arc intersecting arc drawn in previous step at C

Step 6 :  Join BC  &  CD.

Quadrilateral ABCD is constructed.

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