Construct a quadrilateral ABCD in which AB = 4.3 cm, BC = 5 cm. LA = 60°. LB = 100° and LD = 95°.
With picture
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Step-by-step explanation:
Draw AB = 4 cm.
At A, draw ∠PAB = 120°.
At B, draw ∠QBA = 60°.
From BQ, cut BC = 4.5 cm.
From C, draw an arc of radius 5 cm which meets AP at D.
Join CD.
Thus ABCD is the required quadrilaterals
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