Question

Construct a quadrilateral ABCD in which AB = 4 cm, BC = 3.8 cm, AD = 3 cm, diagonal AC = 5 cm and diagonal BD = 4.6 cm. (write steps of construction​

Answer 1

Answer:

-Take a straight line AB= 4 cm

-then on the compass measure a distance of 3.8 cm this is your BC, now put the needle of the compass on point B and make an big arc over B

- now take the compass and measure the distance 5 cm this is your diagonal AC, put the needle of the compass on point A and drawn an arc towards the arc you made before over B, you should get an intersecting point of the 2 arch's mark it as C

- next take measure a distance of 3 cm this is your AD place the compass over A and drawn an arc.

- then again measure the distance of 4.6 cm this is your diagonal BD and put the compass on B and draw an arc towards the arc of Ad you drew in the step above; you should get an intersecting point mark this point as D

- Finally you see you have all the four points now join the points with straight lines and your quadrilateral ABCD is done.

Hope it helps! Follow and mark as brainliest!

Answer 2

Step-by-step explanation:

1 draw a line segment of 4 cm AB

2with the help of scale and compass measure 3cm and with A as a centre cut an arc

3 similarly measure 4.6 cm and B as a centre cut an arc which intersects the previous arc at point D. join AD and BD

4 with the help of scale and compass measure 3.8 cm and B as a centre cut an arc on another side

5 similarly measure 5cm and A as a centre cut an arc which cuts the previous arc at C

6 join BC and AC

7 join CD

therefore ABCD is required quadrilateral