construct a quadrilateral ABCD in which AB equal to 4cm AC equal to 5cm AD equal to 5.5 5cm and angle ABC equal to angle ACD equal to 90 degree
Answers
Answered by
2
By pythagoras theorem find BC
BC= 3 CM
draw AB=4cm
taking B as center, make an angle of 90 degree
on ray B, mark an arc of 3 cm and name it C
Join AC (diagonal of quad) ( it will automatically be equal to 5 cm)
on line AC, taking C as center, draw again 90 degree angle. Because angle ABC= angle ACD = 90 degree
on ray C, from pt. A draw the line = to 5.5 cm n mark the point of intersection as D now, ABCD is the req. quad
BC= 3 CM
draw AB=4cm
taking B as center, make an angle of 90 degree
on ray B, mark an arc of 3 cm and name it C
Join AC (diagonal of quad) ( it will automatically be equal to 5 cm)
on line AC, taking C as center, draw again 90 degree angle. Because angle ABC= angle ACD = 90 degree
on ray C, from pt. A draw the line = to 5.5 cm n mark the point of intersection as D now, ABCD is the req. quad
Similar questions