Question

construct a quadrilateral ABCD when BC is equal to 5.5 CM CD is equal to 4.1 CM angleA is equal to 60 degree angle b is equal to 120 degree and Angle d is equal to 90 degree

Answer 1

First we have to draw a Rough sketch ABCD for our help

three angles are given so we have to find the third angle by angle sum property of quadrilateral
60°+120°+90°+x=360°
270°+x=360°
x=360°-270°
x= 90°
So,angle BCD =90°
STEP 1-Draw DC=4.1cm
STEP 2-Draw angle BCD=90°
STEP 3-taking C as centre and radius 5.5cm draw an arc intersecting previous line at B.
STEP 4-Taking B as centre draw angle=120°
STEP 5-Taking D as centre draw 90° angle intersecting previous line at A
angle BAD should be 60°
Thus, quadrilateral is formed

Answer 2

Answer:

Step-by-step explanation:

First we have to draw a Rough sketch ABCD for our help

three angles are given so we have to find the third angle by angle sum property of quadrilateral

60°+120°+90°+x=360°

270°+x=360°

x=360°-270°

x= 90°

So,angle BCD =90°

STEP 1-Draw DC=4.1cm

STEP 2-Draw angle BCD=90°

STEP 3-taking C as centre and radius 5.5cm draw an arc intersecting previous line at B.

STEP 4-Taking B as centre draw angle=120°

STEP 5-Taking D as centre draw 90° angle intersecting previous line at A

angle BAD should be 60°

Thus, quadrilateral is formed

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