construct a quadrilateral ABCD where BC equal to 5 cm ab is equal to 3.9 CM angle A equal to 90 degree angle B equal to 105 degree and Angle c equal to 75 degree measure other two angel
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First we have to draw a Rough sketch ABCD for our help
three angles are given so we have to find the third angle by angle sum property of quadrilateral
60°+120°+90°+x=360°
270°+x=360°
x=360°-270°
x= 90°
So,angle BCD =90°
STEP 1-Draw DC=4.1cm
STEP 2-Draw angle BCD=90°
STEP 3-taking C as centre and radius 5.5cm draw an arc intersecting previous line at B.
STEP 4-Taking B as centre draw angle=120°
STEP 5-Taking D as centre draw 90° angle intersecting previous line at A
angle BAD should be 60°
Thus, quadrilateral is formed
Step-by-step explanation:
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