Math, asked by UjjVis, 5 months ago

construct a quadrilateral ABCD where BC equal to 5 cm ab is equal to 3.9 CM angle A equal to 90 degree angle B equal to 105 degree and Angle c equal to 75 degree measure other two angel​

Answers

Answered by Anonymous
0

Answer:

First we have to draw a Rough sketch ABCD for our help

three angles are given so we have to find the third angle by angle sum property of quadrilateral  

60°+120°+90°+x=360°

270°+x=360°

x=360°-270°

x= 90°

So,angle BCD =90°

STEP 1-Draw DC=4.1cm

STEP 2-Draw angle BCD=90°

STEP 3-taking C as centre and radius 5.5cm draw an arc intersecting previous line at B.

STEP 4-Taking B as centre draw angle=120°

STEP 5-Taking D as centre draw 90° angle intersecting previous line at A

angle BAD should be 60°

Thus, quadrilateral is formed

Step-by-step explanation:

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