Math, asked by kantjharaju, 7 months ago

construct a quadrilateral ABCD with BC=5.5 cm , CD=4cm , DA= 4cm , angle c = 90° and angle D = 85°​

Answers

Answered by merinmathew232
7

Step-by-step explanation:

Quadrilateral ABCD is constructed  in which BC = 5.5 CM CD = 4 cm,

DA= 4CM ,∠C = 90°and ∠D = 85°

Step-by-step explanation:

Step 1 : Draw a line segment DC = 4 cm

Step 2 : Construct  an angle of 90° using protractor at point C.

Step 3 : Take a length of 5.5 cm from C at angle drawn in step 2 and label the other point as B.

Step 4 : Draw an angle of 85° at D using Protractor.

Step 5 : Take a length of 4 cm from D and label the other point as A

Step 6 : Join AB

quadrilateral ABCD is constructed.

Attachments:
Answered by vaibhav5372
0

Step-by-step explanation:

1-Draw a line CD of 4 cm

2-Construct an angle of 90° at point C

3-Take 5.5cm length an mark an arc from point C and mark it as point B

4-Draw an angle of 85° at point D with the help of protector

5-Take length of 4cm from ruler and mark an arc and name it as point A

6-Join point B and point A

Thus ABCD is an required quadrilateral

Attachments:
Similar questions