Question

construct a quadrilateral pqrs in which PR is= 6 CM ,QS =8cm and the angle between the two diagonal. ​

Answer 1

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We know that, sides of rhombus are equal.

So, PQ=QR=RS=PS=6cm

⇒ Draw a line segment PQ=6cm

⇒ Take P as center with radius 8cm and draw an arc.

⇒ Take Q as center with radius 6cm and draw an arc, which meets previous arc at point R.

⇒ Take P as center with radius 6cm and draw an arc.

⇒ Take R as center with radius 6cm and draw an arc, which meets previous arc at point S.

⇒ Join QR,RS,SP,PR and QS

∴ PQRS is a required rhombus.

⇒ Measure the length of QS.

We get QS=8.9cm