Question

construct a quadrilateral pqrs in which PS is 4 cm PQ is 5 cm QR is 2.5 CM and < p = 60 degree and < Q = 85 degree​

Answer 1

Step-by-step explanation:

Steps of Construction:

(i) Construct a line segment QR = 5 cm.

(ii) At the point Q, construct a ray QX making an angle of 60

⋅

and cut off QP = 4 cm.

(iii) At the point R, construct a ray RY making an angle of 90

⋅

and cut off RS = 4.5 cm.

(iv) Now join PS.

Therefore, PQRS is the required quadrilateral.