Construct a rectangle whose length is twice its width and perimeter is equal to the perimeter of a rhombus of side 6 cm.
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Answers
Answer:
length = 8
width = 4
Step-by-step explanation:
let the length be 2x
and width be x
according to the question,
2x + 2x + x + x = 24 {bcz perimeter(rhombus) =
sum of all side}
6x = 24
x = 24÷6
x = 4
therefore,. 2x= 8
steps of construction,
- draw a line AB of 8cm
- construct an angle of 90°
- cut an arc from point A to point D of 4cm
- simillarly construct angle of 90° and cut ar of 4cm from point B to C
- join CD
- Rectangle is ready.
Hope it will help you..
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Let breadth be x cm
Then,
Length = 2x cm
Perimeter of radius = 4 × sides
= 4 × 6
= 24 cm
Perimeter of rectangle = 2( l + b )
According to the question,
=> 2 ( x + 2x ) = 24
=> ( 2 × x )+( 2 × 2x ) = 24
=> 2x + 4x = 24
=> 6x = 24
=> x = 24/ 6
=> x = 4
Therefore,
Breadth = x = 4cm
Length = 2x = 2 × 4 = 8cm .
Step-by-step explanation:
Steps Of Construction :-
(i) We draw a line segment AB = 8 cm.
(ii) At A construct 90° using compass.
(iii) Cut off AD from ray XA = 4 cm.
(iv) At B construct 90° using compass.
(v) Cut off BC from ray YB = 4 cm.
(vi) Join DC .