Question

Construct a rectangle whose length is twice its width and perimeter is equal to the perimeter of a rhombus of side 6 cm.
attach pic.....​

Answer 1

Answer:

length = 8

width = 4

Step-by-step explanation:

let the length be 2x

and width be x

according to the question,

2x + 2x + x + x = 24 {bcz perimeter(rhombus) =

sum of all side}

6x = 24

x = 24÷6

x = 4

therefore,. 2x= 8

steps of construction,

- draw a line AB of 8cm

- construct an angle of 90°

- cut an arc from point A to point D of 4cm

- simillarly construct angle of 90° and cut ar of 4cm from point B to C

- join CD

- Rectangle is ready.

Hope it will help you..

Please mark it brainliest

Answer 2

Let breadth be x cm

Then,

Length = 2x cm

Perimeter of radius = 4 × sides

= 4 × 6

= 24 cm

Perimeter of rectangle = 2( l + b )

According to the question,

=> 2 ( x + 2x ) = 24

=> ( 2 × x )+( 2 × 2x ) = 24

=> 2x + 4x = 24

=> 6x = 24

=> x = 24/ 6

=> x = 4

Therefore,

Breadth = x = 4cm

Length = 2x = 2 × 4 = 8cm .

Step-by-step explanation:

Steps Of Construction :-

(i) We draw a line segment AB = 8 cm.

(ii) At A construct 90° using compass.

(iii) Cut off AD from ray XA = 4 cm.

(iv) At B construct 90° using compass.

(v) Cut off BC from ray YB = 4 cm.

(vi) Join DC .