construct a rhombus ABCD in which AB is equal to 4.5 cm and diagonal AC is equal to 6 CM
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First draw AB. Then taking A as center draw 6 cm ( that is the length of AC). Then take 4.5 cm and cut the 6 cm arc. U got point C. Now taking A & C as centre draw arc of 4.5 cm. The point they intersect is D. Join the lines. Rhombus ABCD is constructed.
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