Construct a rhombus FAST with its diagonals FS = 10 cm and AT = 8 cm
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Answered by
37
Step1: Draw a line of 10 cm FS
Step2: with the help of compass take a distance more than half and bisect it at T and A
Step3: now meet T and A
step4: through centre cut this of 4 cm in upper and lower for make 8 cm
Now meet T and F,T and S , F and A, S and A
Hope you understand
Step2: with the help of compass take a distance more than half and bisect it at T and A
Step3: now meet T and A
step4: through centre cut this of 4 cm in upper and lower for make 8 cm
Now meet T and F,T and S , F and A, S and A
Hope you understand
Answered by
3
Answer:
Step=1. Draw FS=10CM
Step=2. Draw perpendicular bisector of FS, intersecting FS at O
Step=3.With O as center and 1/2×AT,i.e.1/2×8=4,as radius, draw arcs on both sides of FS at A and T.
Step=4.Join FA,AS,ST,FT.
The quadrilateral, FAST thus obtained, is the required rhombus
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