Question

Construct a rhombus PQRS whose diagonals PR = 7.2 cm and QS = 5.4 cm.​

Answer 1

Steps of construction:

Steps of construction:(i) Draw a line segment PR=8cm

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3 cm each.(by drawing 3 cm arc from O along XY line)

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3 cm each.(by drawing 3 cm arc from O along XY line)(iv) Join PQ,QR,RS and SP

Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3 cm each.(by drawing 3 cm arc from O along XY line)(iv) Join PQ,QR,RS and SPThus, PQRS is the required rhombus.

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Answer 2

Answer:

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