Question

Evaluate : 9^-1 x 2^4 / 18^2

Answer 1

To find : $(9^{-1} )\times (\frac{2^{4} }{18^{2} } )$

Solution :

• Multiplication is a process of repetitive addition of integers.

• Multiplication rules for integers :

1. If two negative integers are multiplied then the product obtained is positive integer. i.e. $(-) \times(-)=+$
2. If one negative and one positive integers are multiplied then the product obtained is negative integer. i.e. $(-) \times(+)=-$
3. If both positive integers are multiplied then the product obtained is positive integer. i.e. $(+) \times(+)=+$

• Therefore according to above rule we solve .
• $(9^{-1} )\times (\frac{2^{4} }{18^{2} } )$  

       $= \frac{1}{9} \times \frac{1^{4} }{9^{2} } \\= \frac{1}{729} \\=0.0013$

 Hence, $\frac{1}{729}$ or $0.0013$ is the product.