Question

The value of 6a²b² - 4ab, where a = 2& b = 1 is

Answer 1

Given: The equation is$6a^{2} b^{2} - 4ab$ and$a = 2\ and\ b = 1$.

We have to solve the above equation.

As we know that the values of a and b are given.

So by putting these values in the above equation, we are solving the above equation.

We are solving in the following way:

We have,

$6a^{2} b^{2} - 4ab$ and$a = 2\ and\ b = 1$

Now,

$=>6 \times2^{2} \times 1^{2} -4\times2\times1\\=>6\times4\times1-8\\=>24-8\\=>16$

Hence, the solution of the above equation is$16$.

Answer 2

• We have to evaluate the above expression by using the given data.

              Given data:- $6a^{2} b^{2} -4ab.$

              To find:- Value of above expression.

              Solution:-

• To solve the above equation we will follow the BODMAS rule.

• BODMAS is an order of mathematic operations.

• BODMAS rule is to be followed while solving expressions in mathematics. It stands for,

          B= bracket

           O= order of power or rules

           D= division

           M= multiplication

           A= addition

           S= subtraction

        Now put the value a=2,b=1.in the given equation we get,

           $6a^{2} b^{2} -4ab\\=6(2)^{2} (1)^{2} -4(2)(1)\\=6\times4\times1-4\times2\times1\\=24-8\\=16.$

         Hence we will get the value $6a^{2} b^{2} -4ab=16.$