Question

Construct a rhombus the lengths of whose diagonals are 6 cm and 8 cm. Measure the length of sides of Rhombus.

Answer 1

Answer:

Step-by-step explanation:

it is not possible to construct a rhombus .

but first find the area by the formula 1/2 * d1 * d2 then find out the side

Answer 2

ㅤㅤHere is Your Solution

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1. A rhombus
2. Diagonals = 6cm and 8 cm

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• The length of sides of Rhombus.

$\large{\fcolorbox{purple}{yellow}{\red{\underline{{\green{STEPS}}}}}}\Large :$

$\bold\pink ❂\red 1.$ Draw a line segment PR = 8 cm.

$\bold\pink ❂\red 2.$ Draw the perpendicular bisector XY of the line segment PR. Let O be the point of intersection of PR and XY, so that O is the 8 cm mid-point of PR.

$\bold\pink ❂\red 3.$ From OX, cut a line segment OS = 3 cm and from OY, cut a line segment OQ = 3 cm.

$\bold\pink ❂\red 4.$ Join PS, SR, RQ and QP, then PQRS is the required rhombus.

$\bold\pink ❂\red 5.$ Measure the length of segments PQ, QR, RS and SP, each is found to be 5 cm long.

$\large\bf \red{\underline{ \green{\underline{\red{N}\green{O}\orange{T}\pink{E}\:\red{✑}\purple{}}}}}$ Don't Forget to check the attachment.

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