Math, asked by Sakshidas4696, 5 months ago

Construct a rhombus whose diagonals are 12 cm and 5 cm.

Answers

Answered by jiya9797
1

Draw a line segment AC=16cm

⇒  Draw a perpendicular bisector of AC, which intersect AC at point O.

⇒  Take O as center with radius 6cm and draw an arc above and below on perpendicular, We get point B and D

⇒  Join AB,BC,CD and AD

∴  ABCD is required rhombus.

The properties which we have used are :

⇒  The intersection of the diagonals of a rhombus form 90 degree angles.  This means that they are perpendicular.

⇒  The diagonals of a rhombus bisect each other.  This means that they cut each other in half.

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Answered by Ayush4441234
0

Answer:

Step-by-step explanation:

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