Question

construct a rhombus whose diagonals are 5.2 CM and 6.4 cm long​

Answer 1

$\Large\bold{\underline{\underline{Step\;of\;Construction}}}$

1. Draw a line segment AC = 5.2cm.
2. Draw a perpendicular bisector on AC.
3. Since, diagonals bisect at mid-point O, therefore get half of 6.4cm, i.e, 3.2cm.
4. draw two ârse on both sides of AC of radius 3.2 cm from intersection point O, which intersects at B and D.
5. join AC, BD, DC, AB, and AD.

This is required Rhombus ABCD.

Answer 2

Answer:

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